sum of the digits of a two digit number is 12. the number formed by interchanging the digits is greater than the original number by 54. find the original number
Answers
Answered by
0
HI there !
Let the no: in unit place be "y" and in ten's place be "x"
The original no: would be 10x + y
Given :-
x + y = 12 ----> (1)
When the digits are interchanged , the no: would be 10y+x
A.T.Q ,
10x + y + 54 = 10y + x
10x + y + 54 - 10y - x = 0
9x - 9y = -54
9(x - y) = -54
x - y = -6 ---> (2)
Adding equations (1) and (2) , we get :-
x + y = 12
x - y = -6
========
2x = 6
x = 3
x + y = 12
3 + y = 12
y = 9
====================================
The original no: is :-
10x + y
10 × 3 + 9
= 39
The original no: is 39
Let the no: in unit place be "y" and in ten's place be "x"
The original no: would be 10x + y
Given :-
x + y = 12 ----> (1)
When the digits are interchanged , the no: would be 10y+x
A.T.Q ,
10x + y + 54 = 10y + x
10x + y + 54 - 10y - x = 0
9x - 9y = -54
9(x - y) = -54
x - y = -6 ---> (2)
Adding equations (1) and (2) , we get :-
x + y = 12
x - y = -6
========
2x = 6
x = 3
x + y = 12
3 + y = 12
y = 9
====================================
The original no: is :-
10x + y
10 × 3 + 9
= 39
The original no: is 39
Similar questions