Sum of the digits of a two digit number is 14. The number obtained by interchanging the digit exceeds the given number by 36. Find the number.
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Let us assume, the two digits of a two-digit number are x and y
Therefore, Two-digit number is = 10x + y and reversed number = 10y + x
Given:
x + y = 14 ------------1
Ans also given:
10y + x = 10x + y + 36
9y - 9x = 36
y - x = 4 --------------2
Subtract equation 2 from 1
2x = 10
x = 5
Therefore y = 14 - x = 14 - 5 = 9
Therefore, two-digit number = 10x + y = (10 * 5) + 9 = 59
Therefore, Two-digit number is = 10x + y and reversed number = 10y + x
Given:
x + y = 14 ------------1
Ans also given:
10y + x = 10x + y + 36
9y - 9x = 36
y - x = 4 --------------2
Subtract equation 2 from 1
2x = 10
x = 5
Therefore y = 14 - x = 14 - 5 = 9
Therefore, two-digit number = 10x + y = (10 * 5) + 9 = 59
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