Sum of the digits of a two digit number is 15. If the number formed by reversing the digits is less than the original number by 27, find the new number.
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Let two digit number be 10x+y
x+y=15_________(1)
Number formed by reversing is 10y+x
10y+x=10x+y- 27
9x-9y=27
x- y=3_________(2)
From (1)&(2)
(1)+(2)
2x=18
x=9
therefore y=6
Thus, the new number is 69
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x+y=15_________(1)
Number formed by reversing is 10y+x
10y+x=10x+y- 27
9x-9y=27
x- y=3_________(2)
From (1)&(2)
(1)+(2)
2x=18
x=9
therefore y=6
Thus, the new number is 69
Hope the answer helps you
Please do mark as brainliest
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