Sum of the digits of a two digit number is 15 . If the number formed by reversing the digits is less than the original number by 27 , find the new number
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Sol:
Let the number with two digits be 10x + y.
Sum of the digits is 15.
⇒ x + y = 15 ----------------- (1)
Number formed by reversing the digits = (10y + x)
(10x + y) - (10y + x) = 27
⇒ 9x - 9y = 27
⇒ x - y = 3 ----------------- (2)
Solving equations (1) and (2), we get x = 9 and y = 6.
Therefore, the original number is 10(9) + 6 = 96.
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let the first digit be x second digit =15-x the number is 10(x) + 1 (15-x) =9x + 15 if we reverse, 10 (15-x)+1(x) 150-9x now 9x+15-(150-9x)=27 18x-135=27 18x=162 x=9 New number = 150-9x 69
madanpassi1:
let the first digit be x
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i think it is the right answer
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