Question

Sum of the digits of a two digit number is 15 . If the number formed by reversing the digits is less than the original number by 27 , find the new number

Answer 1

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Answer 2

$<b>Hello Mate!$

Let tens digit of the original number be x

And one's digit = (15 - x)

so original number,

10(x) + (15-x) 

reversing digits mean

10(15-x) + x

therefore

[10(x) + (15-x)]-[10(15-x)+x] = 27

or  10x + 15-x - 150+10x-x = 27

or 10x + 10x + 15 - 150 -x - x = 27

or 20x - 135 -2x = 27

or 18x - 135 = 27

or 18x = 27 + 135

or 18x = 162

or x = 162/18

or x = 9

original number = 10(x) + (15-x) 

                              = 10(9) + (15-9)

                              = 90+6

                              = 96


Thanks for the question!