Question

sum of the digits of a two digit number is 15.the number obtained by interchange the digits exceeds the given number by 9. find the number​

Answer 1

One digit=x,another digit=15-x

Let x be the tens digit and 15-x is in ones digit.

actual no=10x+15-x=9x+15

When interchanged,=10(15-x)+x=150-10x+x=150-9x

ATQ

=>9x+15+9=150-9x

=>9x+9x=150-24

=>18x=126

=>x=126/18=7

The no.=9x7+15=63+15=78

Answer 2

Hope this helps.

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