Question

sum of the digits of a two-digit number is 5 and the difference of the original number and the number formed by reversing the digit is 9 find the original number​

Answer 1

Answer:

The number is 23

Step-by-step explanation:

The sum of 2 and 3 is 5

the difference of the original number and the number formed by reversing the digit = 32 - 23

= 9

So your answer is 23

Answer 2

SOLUTION :-

Let,

Digit in ten's place = x

Digit in one's place = y

Original number = 10x + y

According to the first condition,

$\longrightarrow\sf x+y = 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ......................(1)$

According to the second condition,

$\longrightarrow\sf (10x+y)-(10y+x) = 9 \\\\\longrightarrow 10x+y-10y-x = 9 \\\\\longrightarrow 9x-9y = 9 \\\\\longrightarrow x - y = 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ......................(2)$

Eq (2) + Eq (1),

$\longrightarrow\sf 2x = 6 \\\\\longrightarrow \bf x = 3$

Substitute the value of x in eq (1),

$\longrightarrow\sf 3+y= 5 \\\\\longrightarrow\bf y = 2$

Original number = 32