Question

Sum of the digits of a two digit number is 5. If the difference between the number and the reversed number is 27. Find the number.

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Answer 1

Answer:-

Let the digit at ten's place be x and digit at one's place be y.

→ The number = 10x + y

Given:

Sum of the digits = 5

⟶ x + y = 5

⟶ x = 5 - y -- equation (1).

Also,

Difference between original number & reversed number = 27

⟶ Original number - Reversed number = 27

⟶ 10x + y - (10y + x) = 27

Substitute the value of x from equation (1)

⟶ 10(5 - y) + y - 10y - (5 - y) = 27

⟶ 50 - 10y + y - 10y - 5 + y = 27

⟶ - 18y = 27 - 50 + 5

⟶ - 18y = - 18

⟶ y = - 18 / - 18

⟶ y = 1

Substitute the value of y in equation (1).

⟶ x = 5 - y

⟶ x = 5 - 1

⟶ x = 4

Hence,

• Required number = 10(4) + 1 = 41

Answer 2

Answer:

ANSWER:-

THE DIGIT AT TENS PLACE BE Y AND AT ONES PLACE BE X AND,

YOU MUST KNOW WHICH ONE IS THE TENS PLACE AND ONE PLACE

NOW,

=> THE NUMBER = 10Y+X

GIVEN:-

SUM OF DIGITS =5

=>Y + X =5

=>y= 5 -X EQUATION (1) EQUATION 1

ALSO,

DIFFERENCIATE BETWEEN ORGINAL VALUE GIVEN AND REVERSED NUMBER VALUE =27

NOW,

[ORIGINAL NUMBER- REVERSED NUMBER ]

THE ABOVE IS THE FORMULA TO DO

NOW PUTTING THE VALUE FROM ABOVE FORMULA

=> 10 Y + X- (10X +Y)=27

NOW, SUBSTITUTE THE VALUE OF "X FROM EQUATION 1"

=>10(5-X)+X-10X-(5-X) =27

=>50-10X +X-10X -5+X =27

=>-18X= 27-50+5

=>-18X= -18

=>X = -18 /-18

=> X = 1 [ - × - = +]

SUBSTITUTE THE VALUE OF X IN EQUATION (1)

=>Y = 5 -X

=> Y = 5 - 1

=> Y = 4

HENCE THE REQUIREMENT ANSWER TO YOUR QUESTION IS

10(4)+1=41

KNOW MORE!

WE KNOW ,

-×- = +

+×+=+

+×- = -

-×+= -