sum of the digits of a two digit number is 6.when we interchange the digits ,it is found that the resulting new number is greater than the original number by 2.what is the two digit number?
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=let the two no. be x and y
their sum is 6 therefore, the no. is
= x+y=6
let the x be in 10's place and y in one's place
=10x+y
the new no. after enterchanging
=10y+x
According to question the new no. is 2 greater than the original no.then,
10x+y-2=10y+x
10x-x-2=10y-y
9x-2=9y
9x-9y=2
9(x-y)=2
x-y=2/9
ATQ
x+y=6
+x-y=2/9
2x=2/9+6
2x=2/9+54/9
x=56/9*2
x=48/9
SAMOASA:
thanks
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