Question

Sum of the digits of a two digit number is 7.When we interchange the digits of this number, it is found that the resulting number is greater than the original number by 25. Find the original number:-​

Answer 1

Answer:

divide it from 7*3 and +1 you will get the original

Answer 2

let the unit digit place of a two number be x

tens place digit =7-x

let the two digit number be 10(7-x) +x

when the number is interchangd 10x+(7-x)

new number is = old number +25

10(7-x) +x+25

10x+7-x=10(7-x) +x+25

9x+7=70-10x+x+25

9x+7=95-9x

9x+9x=95-7

18x=88

x=88/18

x=4.8

ten place digit =9-x

=9-4.8

=4.2

=10(9-x) +x

=10(9-4.8)+4.8

= 9-48+4.8

= 39+4.8

=43.8

i hope it is helpful