Sum of the digits of a two-digit number is 8.Find the 2-digit number if both the digits are equal.
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Answered by
0
Answer:
Let the two-digit number be 10x+y
Then, we have : x+y=8
and 10y+x=10x+y−54or,x−y=54/9=6
Solving equations (1) and (2), we get
x=(8+6)/2=7 and y=1
∴ The required number =7×10+1=71
Answered by
0
Answer:
4
Step-by-step explanation:
given:
the sum of two digit no.=8
both the no.s are same
so let the 1st no. is x
so second no. is also be x
equation=x+x=8
=2x=8
=x=8÷2
=x=4
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