Math, asked by pratha10007, 3 months ago

Sum of the digits of a two-digit number is 8 if the original number is greater than the number formed by reversing the digits by 36 find the original number​

Answers

Answered by hhhamzamallick009
0

Answer:

35

Step-by-step explanation:

Let the tens digit=x

and units digit=y

Hence sum x+y=8…………(i)

Number =10x+y

Number formed by reversing the digits =10y+x

(10y+x)=(10x+y)+18 i . e. 9y-9x=18

Or y-x=2…………..(ii)

Adding (i) and (ii) gives 2y=10

Hence y=5

hence from (i) x=8-y=8–5=3

hence Number =35

hope it help

please mark brainliest :)

Answered by aksh000
0

Answer:

let the first no. be x and second no.be 8-x

so the no. formed is 10x+ 8-x(as x is in tens place)

if we reverse the digits the no.formed is 10(8-x)+ x

the difference between them is 36 so subtract both of them and get the answer

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