Sum of the digits of a two-digit number is 8 if the original number is greater than the number formed by reversing the digits by 36 find the original number
Answers
Answered by
0
Answer:
35
Step-by-step explanation:
Let the tens digit=x
and units digit=y
Hence sum x+y=8…………(i)
Number =10x+y
Number formed by reversing the digits =10y+x
(10y+x)=(10x+y)+18 i . e. 9y-9x=18
Or y-x=2…………..(ii)
Adding (i) and (ii) gives 2y=10
Hence y=5
hence from (i) x=8-y=8–5=3
hence Number =35
hope it help
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Answered by
0
Answer:
let the first no. be x and second no.be 8-x
so the no. formed is 10x+ 8-x(as x is in tens place)
if we reverse the digits the no.formed is 10(8-x)+ x
the difference between them is 36 so subtract both of them and get the answer
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