Question

Sum of the digits of a two digit number is 8 the number obtained by interchanging the digits exceeds the original number by 18.Find the number. <br />

Answer 1

Let the unit digit of the no. be x

So, tens digit of the no. =8-x

So, no. formed = 10(8-x)+x

=80-10x+x

=80-9x

When digits interchanged

No.formed = 10x+8-x

=9x+8

A/q

80-9x+18=9x+8

-9x-9x =8-80-18

-18x=-90

x=5

No. =80-9×5

=80-45=35