Question

Sum of the digits of a two digit number is 8. When we interchange the digits, it is found that the resulting two digit number is greater than the original number by 6. What is the two digit number?

Answer 1

NOW LET UNIT DIGIT = x

and tens digit = y

son number no. = 10y + x

atq

y+ x = 8

y= 8-x

now

10y + x -6 = 10x + y

9y - 9x = 6

3y-3x = 2

now putting value of 1

3( 8-x) -3x= 2

24-3x- 3x = 2

solve further ypur self

Answer 2

Answer:

Let the unit place be x

then tens place = 8-x

& original number = 10(8-x)+x

= 80 - 10x + x

After interchange of digit , the resulting two digit number will be 10x + 8 - x

according to the question,

10x + 8 - x = 80 - 10x + x

or, 10x - x + 10x - x = 80 - 8

or, 18x = 72

or, x = 72/18

x = 4

Hence the original number = 80 - 10x + x

= 80 - 10 × 4 + 4 (putting the value of x)

= 80 - 40 + 4

= 40 + 4

= 44.