Question

sum of the digits of a two digit number is 9 if 27 is added to the number the digits gets reversed find the number solve the question with one variable

Answer 1

let the digit at ones place be 'x'

Then the digit at tens place=9-x. (sum of two digits is 9)

Therefore number 10(9-x)+X.
=90-10x+X
=90-9x. (1)
now, number obtained by reversing the digits=10*(X)+(9-x)
=10x+9-x
=9x+9
if is given that if 27 is added to the number it's digits are reversed.
therefore, number+27=number obtained by reversing the digits.
(90-9x)+27=9x+9
117-9x=9x+9
117-9=9x+9x
108=18x
x=108/18
x=6
By substituting the value of X in equation (1)we get the number
number=90-9*6
=90-54
=36

Answer 2

Here is your solution

Given :-

The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .

Now

Let ,

x and y are the two digits of a two-digit number.

The two-digit number = 10x + y

reversed number = 10y + x


x + y = 9 ------------1

A/q

10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2

Substract equation 2 from equation 1

2x = 6

x = 3✔


y = 9 - x
y= 9 - 3
y= 6✔


The two digit number = 10x + y = (10 × 3) + 6 = 36.

Hope it helps you