Question

sum of the digits of a two-digit number is 9 the number obtained by interchanging the digits exceeds the given number by 27 find the original number ​

Answer 1

$\mathfrak{\huge{Hi!}}$

$\mathsf{Let\:the\:original\:number\:be = 10x + y}$

Digits = x and y

$\sf{Sum\:of\:digits = x + y = 9}$

x = 9 - y

According to the question :-

$\sf{10y + x = 10x + y + \bf{27}}$

=》 $\sf{10y + 9 - y = 10 ( 9 - y ) + y + 27 }$

=》 $\sf{18y = 108}$

$\boxed{\tt{y = 6}}$

x = 9 - y = 3

$\boxed{\tt{x = 3}}$

$\boxed{\huge{\bf{Number = 36}}}$