Sum of the digits of a two-digit number is 9. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 27. What
is the two-digit number?
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Let the tens place digit be x
And unit place digit be 9-x
So, original no.= 10x+9-x= 9x+ 9
By interchange of digits,
New no .= 90-10x+x= 90-9x
According to the question,
9x+9+27= 90-9x
9x+36= 90-9x
18x= 54
x= 54/18
x= 3
So original no.= 9(3)+9= 27+9= 36
And unit place digit be 9-x
So, original no.= 10x+9-x= 9x+ 9
By interchange of digits,
New no .= 90-10x+x= 90-9x
According to the question,
9x+9+27= 90-9x
9x+36= 90-9x
18x= 54
x= 54/18
x= 3
So original no.= 9(3)+9= 27+9= 36
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