sum of the digits of a two digit number is 9. when we interchange the digits it is found that the resulting new number is greater than the original number by 27 . what is the two digit number
Answers
Answer:
Step-by-step explanation:
Let the unit digit be y and tens digit be x
Number formed = 10x + y
Reverse number = 10y + x
x + y = 9 (Given)…………………………eq1
10y + x = 10x + y + 27…………………….eq2
9y - 9x = 27
y - x = 3……………………………………..eq3
Solving eq1 and eq3 ,we get
x = 3 and y = 6
Original Number = 36 Reversed Number = 63
You can crosscheck the answer by putting up the values obtained either in eq1 or eq2 or eq 3
Thank You !
OR
Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 39 =27
27 = 27 (correct)
The Original Number is 36.
Given :
Sum of the Digits = 9
The number with interchanged digits is greater than the original number by 27.
To Find :
The Number
Solution :
- Units place as x
- Tens place as 10(9 - x)
x + 10(9 - x)
x + 90 - 10x
-9x + 90 ......... [ Original Number ]
- Units Place = (9 - x)
- Tens Place = 10(x)
9 - x + 10x
9 + 9x .......... [ Number with Reversed Digits ]
The number with interchanged digits is greater than the original number by 27.
★
Units Place = 6
★ Value of 10(9 - x)
The Original Number -
The Original Number is 36.
Reversed digits of 36 = 63
Check if 63 is more 36 by 27 or not.
The Original Number is 36.