Sum of the digits of a two-digit number is 9.When we interchange the digit ,it is found that the resulting new number is greater than the original number by27.What is the two digits number?
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Let ones digit no be y and tens digit no be x
No. 10x+y
Interchanging no. 10y+x
X+Y =9 1
10y+x = 10x+y+27
10y+x-10x-y = 27
9y-9x = 27
9(y-x) = 27
Y-x = 3 2
By solving equation 1 and 2 we get
Y =6
X=3
No.= 10x+y
36
No. 10x+y
Interchanging no. 10y+x
X+Y =9 1
10y+x = 10x+y+27
10y+x-10x-y = 27
9y-9x = 27
9(y-x) = 27
Y-x = 3 2
By solving equation 1 and 2 we get
Y =6
X=3
No.= 10x+y
36
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