Math, asked by gauravyadav6143, 10 hours ago

Sum of the digits of a two-digit number is 9. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 27. What
is the two-digit number?

Answers

Answered by preet399
2
Here one of the number is 10x and another is y
Hope it helps
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Answered by rohansuraniya
2

Step-by-step explanation:

let the two digits of a two digit number be x and y

let the two digits of a two digit number be x and yso, the no. will be:

let the two digits of a two digit number be x and yso, the no. will be:10x+y

let the two digits of a two digit number be x and yso, the no. will be:10x+yx+y = 9

let the two digits of a two digit number be x and yso, the no. will be:10x+yx+y = 9another number by interchanging the digits :

let the two digits of a two digit number be x and yso, the no. will be:10x+yx+y = 9another number by interchanging the digits :10y+x

let the two digits of a two digit number be x and yso, the no. will be:10x+yx+y = 9another number by interchanging the digits :10y+xNow,

let the two digits of a two digit number be x and yso, the no. will be:10x+yx+y = 9another number by interchanging the digits :10y+xNow, A. T. Q

10y+x=10x+y+27

10y-10x=y+x+27

10y-10x=9+27 ( as x+y =9 )

10(y-x)=36

y-x=36/10

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