Sum of the digits of a two digit number is 9. when we interchange the digits it is found that the resulting new number is greater than the original number by 63.find the two digit numbers
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let the original number be xy and given that the sum of the digits is 9
⇒ x + y = 9
given that by interchanging digits the new number formed is greater than the original number by 63
⇒ xy + 63 = yx
⇒ 10x + y + 63 = 10y + x
⇒ 9x + 63 = 9y
⇒ 9(x - y) = -63
⇒ x - y = -7 and x + y = 9
⇒ 2x = 2
⇒ x = 1
⇒ y = 8
so the original number is 18 and the digits interchanged number is 81
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