Sum of the digits of a two digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What are the numbers?
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Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 39 =27
27 = 27
hope...it ...helps...
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 39 =27
27 = 27
hope...it ...helps...
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