sum of the digits of a two digit number is 9 when we interchange the digit it is found that the resulting new number is great than the original number by27 what is the two digit number
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A two digit number whose digits add up to 9 is x*10+9-x
adding 27 gives us the reversed digits:
So 10x+9-x+27=10(9-x)+x
9x + 36 = 90–9x
18x = 90–36 = 54
x = 3
So the numbers are 36 and 63
Hope it helps
adding 27 gives us the reversed digits:
So 10x+9-x+27=10(9-x)+x
9x + 36 = 90–9x
18x = 90–36 = 54
x = 3
So the numbers are 36 and 63
Hope it helps
nitin777:
its not a perfect answer
Answered by
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let the tens difit be x
and the ones digit be y
x + y = 9 i)
10y + x = 10x + y + 27
9( x - y ) = - 27
x - y = -3 ii)
now by elimination method
x + y = 9
x - y = -3
x = 6
now putting the value of x in equation i)
x + y = 9
6 + y = 9
y = 3
then the number will be 63
I hope that my answer will help u
and the ones digit be y
x + y = 9 i)
10y + x = 10x + y + 27
9( x - y ) = - 27
x - y = -3 ii)
now by elimination method
x + y = 9
x - y = -3
x = 6
now putting the value of x in equation i)
x + y = 9
6 + y = 9
y = 3
then the number will be 63
I hope that my answer will help u
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