Question

Sum of the digits of a two digit number is 9. When we interchange the digit, it is found that the resulti6 new number is greater than the original number by 27. What is the two digit number?

Answer 1

Let the digit at units place be X.

Then the digit at tens place =9-x

Original number =10(9-x) +x

90-9x

After interchanging,

Digit at units place=9-x

Digit at tens place=x

New number =10x+9-x=9x+9

Acc. To question,

(9x+9)-(90-9x)=27

9x+9-90+9x=27

18x-81=27

18x=27+81=108

X=108/18=6

& 9-x=9-6=3

So the original number is 36