sum of the digits of a two digits number is 10.the number obtained by reserving the digits is 36 grater than the original number find the number
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Step-by-step explanation:
let the no. is 10x+y.
sum of the digits of a two digits number is 10
A/q
x+y = 10....(1)
After reversing the digit, it become 10y+x.
number obtained by reserving the digits is 36 grater than the original number,
A/q
10y+x = 10x+y + 36
=> 9y - 9x = 36
=> 9(y-x) = 36
=> y-x = 4
=> y = 4+x ......(2)
Now put eq. (2) in (1).
x + 4+x = 10
=> 2x = 6
=> x = 3
So, y = 4+x = 4+3 = 7
So the original no. is 37.
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