Sum of the digits of a two digits number
is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number
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let unit place digit = x
ten place digit=y
x+y=11....(1)
10x+y=x+10y-9
9x-9y=-9
x-y=-1...(2)
then x=11-y
put value of x in(2)
11-y-y=-1
2y=12
y=6
put value of y in x=11-y
x=11-6
x=5
then number=x+10y
=5+60
=65
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