Question

Sum of the digits of a two digits number is 9. The number obtained by interchanging of the digits/ exceed the given number by 27 find the number

Answer 1

Answer:

36

Step-by-step explanation:

Let that number is 10a+b

sum of the digits a+b= 9       (1)

10b+a-(10a+b)=27

10(b-a)-(b-a)=27

(b-a)(10-1)= 27

b-a = 27/9

b-a = 3                                 (2)

by adding 1 and 2

2b = 12

b= 6

a+6=9

a=3

Answer 2

Answer:

hey mate

let the no. at ones place be "x"

and no. at tens place be"9-x"

original no.

tens ones

9-x x

so, original no.=1*x+10(9-x)

=x+90-10x

original no=90-9x

on reversing

tens ones

x 9-x

so, new number=1(9-x)+10*x

=9-x+10x

new no.=9+9x

A.T.Q

9+9x=90-9x+27

9x+9x=90-9+27

18x= 81+27

18x=108

x=108/18=6

so,the original no.is tens ones

9-x x

9-6 6

and the answer is 36

hope this will help you

good evening