Math, asked by sandeepashish7, 3 months ago

sum of the digits of a two number is 12, the given number exceeds the number obtained by interchanging the digits by 36. Find the given number

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Answered by vvlite82
1

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Answered by Anonymous
13

A N S W E R :

  • Original number is 84.

\underline{\frak{\qquad Given :\qquad}} \\  \\

  • Sum of the digits of a two number is 12, the given number exceeds the number obtained by interchanging the digits by 36.

\underline{\frak{\qquad To \:Find :\qquad}} \\  \\

  • The original number = ?

\underline{\frak{\qquad Solution :\qquad}} \\  \\

\large\bigstar\:\underline{\textsf{Original Number :}} \\  \\

:\implies\sf Original  \: Number = 10(12 - x) + x \\  \\  \\

:\implies\sf Original  \: Number = 120 - 10x + x \\  \\  \\

:\implies\sf Original  \: Number = 120 - 9x\\  \\  \\

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\large\bigstar\:\underline{\textsf{Interchanged Number :}} \\  \\

:\implies \sf Interchanged \:  Number = 10x + 12 - x \\  \\  \\

:\implies \sf Interchanged \:  Number = 9x + 12 \\  \\  \\

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\underline{\boldsymbol{According\: to \:the\: Question\:now :}}\\

\dashrightarrow\:\:\sf Original \:  Number - 36 = Interchanged \:  Number \\  \\  \\

\dashrightarrow\:\:\sf 120 - 9x - 36 = 9x + 12\\  \\  \\

\dashrightarrow\:\:\sf 84- 9x = 9x + 12\\  \\  \\

\dashrightarrow\:\:\sf 84- 12 = 9x + 9x\\  \\  \\

\dashrightarrow\:\:\sf 72 = 18x\\  \\  \\

\dashrightarrow\:\:\sf x =  \dfrac{72}{18} \\  \\  \\

\dashrightarrow\:\: \underline{ \boxed{\sf x = 4}} \\  \\  \\

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\large\therefore\: \underline{\textsf{The given original number is :}} \\  \\  \\

\bullet\:\textsf{Original Number = 120 - 9x = 120 - 9(4) = 120 - 36 = \textbf{84}} \\  \\

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