sum of the digits of a two-year digit number is 12. If the digits are reversed, the new number so formed increases by 36. find the number.
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let the digits be x and y
x+y=12
xy-yx=36
we know that the difference is 36 so 36/9= 4
so the digits differ by 4
and x+(x+4 or y)= 12
x=4
y=8
so the no. is 48
x+y=12
xy-yx=36
we know that the difference is 36 so 36/9= 4
so the digits differ by 4
and x+(x+4 or y)= 12
x=4
y=8
so the no. is 48
haribol1234p9zix3:
10x+y-(x+y)=10x+y-x-y==9x=18=x=2 and y =1 . so the no. is 21
ans 24
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let the digits be x and y . then , it is given that |xy| - (x+y)= 10(x)+1(y)-(x+y)= 10x+y-x-y= 9x= 18= x= 2 and y=1
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