Question

sum of the digits of the two digits number is 9 and number formed by interchanging the digits is greater then original number by 27​

Answer 1

Answer:

Let ,the number at once place be y and tens place be x .then the number formed by interchanging is (10x+y)

Step-by-step explanation:

According to first condition,

x+y=9

According to second condition,

or,10x+y+27=10y+x

or,10x+y-10y-x=27

or,9x-9y=27

or,9(x-y)=9*3

x-y=3

Adding both the equation.we get,

x+y=9

x-y=3

2x=12

or,x=12/2

therefore x=6

putting x=6 in equation 1 we get,

x+y=9

or,6+y=9

or,y=9-6

therefore y=3

Hence ,original number is 10x+y

=10*6+3

=63

Hope,this answer will help you.

Best of luck!!!