sum of the digits of two digit is 18. If the digits are reversed the number is 126 more than the original. Find the number
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Let unit place is x and tenth place is y so
Condition 1
x +y = 12
Condition 2 if digit reversed
y +10x = x + 10y -18
y + 10x -x - 10y= -18
9x -9y = -18
9y -9x =18
9y- 9(12–y)= 18
9y-108+9y=18
18y= 18+108
y = 126/18
y= 7
So x = 12–7 =5
Original number = 10x +y = 10x5+7= 57
4.7k views · View Upvoters · Answer requested by Avinash Mishra
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