Question

sum of the digits of two digit no. 7 the difference between original number obtained by reversing the digits is 27 find the original number​

Answer 1

Step-by-step explanation:

Let the ten's place digit be x and unit's place digit be y.

Therefore,

Original number = 10x + y

On reversing the digits:

New number so obtained = 10y + x

According to the given conditions:

x + y = 7...... (1)

10x + y - (10y + x) = 27

$\therefore \: 10x + y - 10y - x = 27 \\ \therefore \: 9x - 9y = 27 \\ \therefore \: 9(x - y) = 27 \\ \therefore \: x - y = \frac{27}{9} \\ \therefore \: x - y = 3......(2) \\ adding \: equations \: (1) \: and \: (2) \\ x + y = 7 \\ x - y = 3 \\ - - - - - \\ 2x = 10 \\ \implies \: x = \frac{10}{2} \\ \implies \huge \boxed{ x = 5} \\ substituting \: x = 5 \: in \: equation \: (1) \\ 5 + y = 7 \\ \implies \: y = 7 - 5 \\ \implies \: \huge \boxed{y = 2} \\ thus \: original \: number \: = 10x + y \\ = 10 \times 5 + 2 = 50 + 2 = 52 \\ \boxed{ \therefore \: original \: number \: = 52}$

Answer 2

Answer:

your answer is in the above picture

mark me has brainlist answer