sum of the digits of two digit number is 9 the number obtained by interchanging two digit exceeds the given number by 27
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Answer:
36 is the correct answer
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Given:-
- The sum of the digits of a two digits is 9.
- The digits are interchanged the number obtained exceeds the original number by 27.
To find:-
- Find the number .?
Solutions:-
- Let the digits at unit's place be y.
- Let the digits at ten's place by x.
Number => 10x + y
The sum of the digits of a two digits is 9.
=> x + y = 9
=> x = 9 - y ............(i).
The digits are interchanged the number obtained exceeds the original number by 27.
=> 10y + x = 10x + y + 27
=> 10x + y + 27 - 10y - x = 0
=> 9x - 9y = -27
=> 9(x - y) = -27
=> x - y = -27/9
=> x - y = -3 ..............(ii).
Putting the value of x in Eq. 2. We get,
=> x - y = -3
=> 9 - y - y = -3
=> -2y = -12
=> y = -12/-2
=> y = 6
Putting the value of y in Eq. 1. We get,
=> x = 9 - y
=> x = 9 - 6
=> x = 3
So, Number => 10x + y
=> 10 × 3 + 6
=> 30 + 6
=> 36
Hence, the number formed is 36.
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