Sum of the exponent of the prime factors of 136 is
Answers
Answered by
1
Answer:
4
Step-by-step explanation:
136=2^3×17^1
here,both 17 and 2 are prime factors
therefore,
3+1(the exponents are adding)
=4
Answered by
2
1,2,4,8,17,34,68 is the answer
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