Question

Sum of the exponents of the prime factors in prime factorization of 196 is

Answer 1

196= 2*2*7*7
=2 square * 7 square
the exponent of 2 is 2
the exponent of 7 is 2
sum of exponents of factors of 196 i.e. 2 square and 7 square = 2+2
=4
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Answer 2

Sum of the exponents of the prime factors in prime factorization of 196 is 4

Solution:

Given that,

We have to find the sum of the exponents of the prime factors in prime factorization of 196

First write the prime factorization of 196

Prime factorization of 196 = $2 \times 2 \times 7 \times 7$

In terms of exponential form,

$\text{Prime factorization of 196 } = 2^2 \times 7^2$

Exponent are 2 , 2

Find the sum of the exponents of the prime factors in prime factorization of 196

Sum of exponents = 2 + 2 = 4

Thus the sum is found

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