Sum of the factors of 4b2c2 - (b2 + c2 - a2) 2 is
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4b² c² - (b² + c² - a²)²
= (2bc)² - (b² + c² - a²)²
= (2bc + b² + c² - a²) (2bc - b² - c² + a²)
= [(b+c)² - a²) (a² - (b-c)²]
= (a + b + c) (b +c - a) (a + b - c) (a-b+c)
= (2bc)² - (b² + c² - a²)²
= (2bc + b² + c² - a²) (2bc - b² - c² + a²)
= [(b+c)² - a²) (a² - (b-c)²]
= (a + b + c) (b +c - a) (a + b - c) (a-b+c)
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Answer:
hey..
Step-by-step explanation:
first answer is right, u can go through that..
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