Sum of the first 10 terms is 50 and the sum of the next 10 terms is 250. find the 15th term in ap
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Hi !
S₁₀ = 50
n/2 [ 2a + (n-1)d ] = 50
10/2 [ 2a + 9d ] = 50
5 [ 2a + 9d ] = 50
2a + 9d = 10 ---------------> [ 1]
=============================================
S₁₀ + S₁₀ = 50 + 250 = 300
S₂₀ = 300
S₂₀ = 20/2 [ 2a + 19d ]
10 [ 2a + 19d ] = 300
2a + 19d = 30 -----------> [2]
(2) - (1)
2a + 19d = 30
- 2a + 9d = 10
=========
10d = 20
d = 2
2a + 9d = 10
2a + 18 = 10
2a = -8
a = -4
==================================
15th term = a₁₅
a₁₅ = a + 14d
= -4 + 14 ×2
= -4 + 28
= 24
S₁₀ = 50
n/2 [ 2a + (n-1)d ] = 50
10/2 [ 2a + 9d ] = 50
5 [ 2a + 9d ] = 50
2a + 9d = 10 ---------------> [ 1]
=============================================
S₁₀ + S₁₀ = 50 + 250 = 300
S₂₀ = 300
S₂₀ = 20/2 [ 2a + 19d ]
10 [ 2a + 19d ] = 300
2a + 19d = 30 -----------> [2]
(2) - (1)
2a + 19d = 30
- 2a + 9d = 10
=========
10d = 20
d = 2
2a + 9d = 10
2a + 18 = 10
2a = -8
a = -4
==================================
15th term = a₁₅
a₁₅ = a + 14d
= -4 + 14 ×2
= -4 + 28
= 24
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