Question

sum of the first 10 terms of the A.P:2,5,8,11​

Answer 1

Answer:

a = 2

d = 5-2 = 3

n = 10

Sum of first 10 terms = n/2(2a+(n-1)d)

                                  = 10/2 (2X2+(10-1)3)

                                  = 5 (4+ 9X3)

                                  = 5 (4+27)

                                  = 5 X 31 = 155

Step-by-step explanation:

Hope it helps you friend :)