Sum of the first 10terms of Ap whose first term is 5 and common difference is also 5
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in the pic bro!
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sn = N/2( a + an )
s10 = 10 /2( 5 + a + ( n -1) 5
s10 = 5 ( 5 + 5 + 5 × 10- 5 )
s10 = 5 ( 5 + 50 )
s10 = 5 ( 55 )
s10 = 275
EXPLANATION :
here a = 5 d = 5 s10 = ?
we dont have an so I substitute the formula in an -----> 1 step
here n = 10 in sn so I substitute the all values in n
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