Sum of the first (n+1) positive integer is:
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sum of the first (N + 1) positive integer is 2
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Sn = n/2 [2a + (n-1)d]
Sn+1 = n+1 / 2 [ 2a + {(n+1) - 1}d]
Sn+1 = n+1 / 2 [2a + nd]
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Sn+1 = n+1 / 2 [ 2a + {(n+1) - 1}d]
Sn+1 = n+1 / 2 [2a + nd]
Hope this will help you!!!
☺☺ Keep smiling ☺☺
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