sum of the first n term of the series root 2 + root 8 + root 18... is plzz
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Step-by-step explanation:
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hope this will help you...btw you have written half question ...
Step-by-Step Explanation :
√2 + √8 + √18 + √32.....n
= 1√2 + 2√2 + 3√2 + 4√2....n
= √2* ( 1 + 2+ 3 + 4 +...n )
= √2* [n* ( n + 1)] / 2
So the sum is :- √2* [ n*( n+1)] / 2
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