sum of the first n terms of an arithmetic progression is n square + 4n . find the 15th term of the progression
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Answer:
solution : let n= 1
= 1+4(1)
=5
let n= 2
= 2+4(2)
= 2+6
= 8
let n= 3
= 3+4(3)
=3+12
= 15
let n = 15
= 15+4(15)
=15+60
=75
now : 5,8,15........…...75
the results is that the 15th term is 75
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