Sum of the first term in an AP is 6 and that of the last three term is
16. If the AP has 13 term what it's the
Sum of middle three terms?
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let first term be a. And common difference is d.
So given a+a+d+a+2d=6
3(a+d) =6
==>|a+d=2
Given that a+12d+a+11d+a+10d=16
3a+33d=16
==> 3(2-d) +33d=16
6+30d=16
==>| d=1/3
Now a=2–1/3 = 5/3
Let's see what are middle terms,
Since no of terms =13. Middle most term =(13+1) /2 th term.
That is 7th term == a+6d
Now middle 3 terms are
a+5d, a+6d, a+7d
Sum of them = 3a+18d
==>sum of middle 3 terms= 5+6= 11
I explained briefly and quickly, so if any doubt is popping in your mind. Ask me in comment section. If Any mistake made by me in calculations plz inform.
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