Question

sum of the interior angles of a regular polygon of n sides is (a)n*90° , (b) (n-2)*90°, (c) n*180°, (d) (n-2) *180​

Answer 1

Answer:

(d) (n-2)×180°

is the answer......

Answer 2

Answer:

We will learn how to find the sum of the interior angles of a polygon having n sides.

We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.

We also know that, the sum of the angles of a triangle = 180°.

Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)

= 2 right angles × (n – 2)

= 2(n – 2) right angles

= (2n – 4) right angles

Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.

Thus, each interior angle of the polygon = (2n – 4)/n right angles.

Step-by-step explanation:

Hoping that will be useful for you