Question

sum of the natural number between 500 and 1000 which are divisible by 105​

Answer 1

Answer: Sum=3675

Step-by-step explanation:

Number between 500 and 1000 which are divisible by 105 can be used to form a series of Arithmetic Progression like

525,630.......945.

Now, taking First term = 525 and common difference = 105,

nth term = 945= 525+(n-1)105

On solving the above equation, we get n=5.

Now Sum of 5 terms of an A.P. =

(n/2)(first term+last term)

=(5/2)(525+945)

=3675

And that's the explanation... Hope it Helped all...:-)