Question

sum of the parallel sides of a trapezium is 25 cm. area of it is 75 sq cm. what is its height?

Answer 1

Answer:

area of trapezium = ½ × ( sum of parallel sides) × height

given,

sum of parallel sides = 25 cm

and area = 75 cm²

putting these values in the above formula.

then,

=> 75 = ½ × 25 × height

$\frac{75 \times 2}{25} = height \\ = > 3 \times 2 = height$

or height = 6 cm.

Step-by-step explanation:

other important formula from mensuration :-

• area of rectangle = length × breath
• perimeter of rectangle = 2( length + breadth)
• area of square = side ²
• perimeter of square = 4* side
• area of circle = πr² ( r is radius)
• circumference of circle = 2π r = πd ( where, d is diameter)

Answer 2

AnSwer -:


Height of the trapezium-: 6.81 cm

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Area of trapezium-:

“A = 1/2 x h x (a+ b )”

A = Area

H = Height

(A + b )= Sum of parallel sides

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Given ,

Area of trapezium-: 75 cm^2

Sum of parallel sides = (a+b) = 22 cm

To find,

Height of the trapezium

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Area of trapezium-:

“A = 1/2 x h x (a+ b )”

Area of trapezium-: A = 75 cm^2

Sum of parallel sides = (a+b) = 22 cm

Height of trapezium-: ??= h

1/2 x h x 22 = 75 cm^2

H = 75 x 2 / 22

H = 150 /22

H = 6.81

Therefore,

Height of the trapezium-: 6.81 cm

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Trapezium-: The trapezium is a

quadrilateral with two parallel sides. The

parallel sides of a trapezium are called

bases.

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