Question

sum of the present age of father and son is 65. 10 years ago their ages was7:2. find their ages? ​

Answer 1

Answer:

sum of ages of both =65

then,

before 10 years ago =65-(10*2)because the sum is of two people ages

=65-20

=45

the ratio of ages = 7:2

the sum of ages=45

then,

7x+2x=45

9x=45

x=45/9

x=5

the age of father = 7x+10

=7*5+10

=45

the age of son = 2x+10

=2*5+10

=20