Question

Sum of the present ages of father and his daughter is 40 years. 4 years ago, father was 31 times as old as his daughter age, find their present age?

Answer 1

Answer:

father age is 35 and daughter age is 5

Step-by-step explanation:

sum of ages=40

let the father and daughter age be x and 40-x

4 years ago x=31(40-x)

so,

x-4=31(40-x-4)

x-4=1240-31x-124

x-4=1116-31x

31x+x=1116+4

32x=1120

x=1120/32

x=35

daughter age is 40-x

40-35

5=daughter age