Sum of the present ages of Manish and Savita is 31. Manish age 3 years ago was
4 times the age of Savita. Frame the equations?
Answers
Answered by
78
Solution :
Let Manish's present age be m years and
Savita's present age be s years
Given :
3 years ago :
• Manish's age = m - 3
• Savita's age = 4 (s - 3)
According to the question:
From equation (i) value of m = 31-s
Putting m = 31-s in equation (ii)
Putting the value of s = 8 in equation (i)
Hence,
• Manish's age = 23 years
• Savita's age = 8 years
Answered by
47
AnsweR :
Sum of the present ages of Manish and Savita is 31. Manish age 3 years ago was 4 times the age of Savita.
Their ages.
Let the present age of Manish be R years.
Let the present age of Savita be M years.
A/q
Now,
So,
Putting the value of M in equation (1), we get;
Thus,
The present age of Manish is 23 years.
The present age of Savita is 8 years.
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