Question

sum of the present ages of Manish and Savita is 31 Manish Age 3 years ago was 4 times the age of Savita find their present ages

Answer 1

Let, the age of Manish = a

age of Savita = b

Sum of their ages is 31 year:

→ a + b = 31

→ a = 31 - b ... (1)

3 years ago:

Manish's age = (a - 3) years

Savita's age = (b - 3) years

In question: that time

→ Manish = 4 * Savita

→ (a - 3) = 4(b - 3)

→ a - 3 = 4b - 12

→ a - 4b = - 12 + 3

→ (31 - b) - 4b = - 9 {a=31 - b}

→ 31 - 5b = - 9

→ 31 + 9 = 5b → 40 = 5b

→ (40/5) = b → b = 8

Putting the value of x in equation 1,

→ a = 31 - 8 = 23 year

Age of manish = a =23 years

Age of manish = a =23 yearsAge of savita = b = 8 years

Answer 2

Answer:

Step-by-step explanation:

Given sum of the present ages of Manish and Savita is 31. Manish's age 3 years ago was 4 times the age of Savita.

Let the age of Manish be x and the age of Savita be y. According to the question the equation is

x + y = 31-----------(1)

x - 3 = 4(y - 3)

x - 3 = 4 y - 12

x - 4 y = - 9---------(2)

Consider equation 1 and 2, we have

x + y = 31

x - 4 y = -9      On subtracting the sign changes.

---------------------

5 y = 40 or y = 8

Substituting y = 8 in equation (1) we have

x + y = 31

x + 8 = 31

x = 31 - 8

x = 23

The age of Manish is 23 yrs and the age of Savita is 8 yrs.